tolong bantu jawab, Kak. terima kasih.
Jawaban:
a.
f(x)= x²-4
y= x²-4
y+4= x²
[tex] \sqrt{y + 4} = x \\ {f}^{ - 1} (x) = \sqrt{x+ 4} [/tex]
b.
(h o g)(x)
[tex] = h(g(x)) \\ = h(g(x)) \\ = h(2x - 3) \\ = \frac{2}{1 - 3(2x - 3)} \\ = \frac{2}{1 - 6x + 9} \\ = \frac{2}{ - 6x + 10} \\ = \frac{1}{ - 3x + 5} [/tex]
c.
(h o g)(3)
masukkan ke rumus tadi:
1/(-3(3)+5))
= 1/(-9+5)
= 1/(-4)
= -1/4
[answer.2.content]
